[cs23021-2] Lab 10 clarification

[Mikhail Nesterenko]

CSI students,

In the 10-th lab, in the header file the output() function was
prototyped as follows:

   // prints the values in "array" of "size" in sorted order
   void output(int *const array, int size);

That is, the pointer to the array was passed as a constant (not to be
modified). However, if, to print the numbers in the increasing order,
you try to use removeNumber() function, the compiler will allow
it. The reason is: the remove number is prototyped as follows

   // removes a "number" from the "array" of "size".
   // if "number" not there -- no action
   // note, "size" changes
   void removeNumber(int *& array, int number, int &size);

Note that the array is passed by reference and can be modified. That
is "array" pointer is not constant. If you try to invoke
removeNumber() from output(), the compiler would generate an error
stating that there is an attempt to convert from constant pointer type
to regular pointer type.

In the header file I updated the output() prototype to non-constant
type:

   // prints the values in "array" of "size" in sorted order
   void output(int *array, int size);

In your implementation, you are free to use either the old (constant)
or the new (non-constant) pointer to the array.

Thanks,
--
Mikhail